335=67x+x^2

Solution for 335=67x+x^2 equation:

335=67x+x^2

We move all terms to the left:

335-(67x+x^2)=0

We get rid of parentheses

-x^2-67x+335=0

We add all the numbers together, and all the variables

-1x^2-67x+335=0

a = -1; b = -67; c = +335;
Δ = b2-4ac
Δ = -672-4·(-1)·335
Δ = 5829
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{5829}}{2*-1}=\frac{67-\sqrt{5829}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{5829}}{2*-1}=\frac{67+\sqrt{5829}}{-2}
$